Google Search

Wednesday, October 5, 2011

Write C++ programs to implement the Kruskal’s algorithm to generate a minimum cost spanning tree


Write C++ programs to implement the Kruskal’s algorithm to generate a minimum cost spanning tree */

#include<iostream>
#include<conio.h>
#include<stdlib.h>
using namespace std;
int cost[10][10],i,j,k,n,m,c,visit,visited[10],l,v,count,count1,vst,p;

main()
{
int dup1,dup2;
cout<<"enter no of vertices";
cin >> n;
cout <<"enter no of edges";
cin >>m;
cout <<"EDGE Cost";
for(k=1;k<=m;k++)
{
cin >>i >>j >>c;
cost[i][j]=c;
cost[j][i]=c;
}
for(i=1;i<=n;i++)
for(j=1;j<=n;j++)
if(cost[i][j]==0)
cost[i][j]=31999;
visit=1;
while(visit<n)
{
v=31999;
for(i=1;i<=n;i++)
for(j=1;j<=n;j++)
if(cost[i][j]!=31999 && cost[i][j]<v  && cost[i][j]!=-1 )
{
int count =0;
for(p=1;p<=n;p++)
{
if(visited[p]==i || visited[p]==j)
count++;
}
if(count >= 2)
{
for(p=1;p<=n;p++)
if(cost[i][p]!=31999 && p!=j)
dup1=p;
for(p=1;p<=n;p++)
if(cost[j][p]!=31999 && p!=i)
dup2=p;

if(cost[dup1][dup2]==-1)
continue;
}
l=i;
k=j;
v=cost[i][j];
}
cout <<"edge from " <<l <<"-->"<<k;
cost[l][k]=-1;
cost[k][l]=-1;
visit++;
int count=0;
count1=0;
for(i=1;i<=n;i++)
{
if(visited[i]==l)
count++;
if(visited[i]==k)
count1++;
}
if(count==0)
visited[++vst]=l;
if(count1==0)
visited[++vst]=k;
}
}

OUTPUT
enter no of vertices4
enter no of edges4
EDGE Cost
1 2 1
2 3 2
3 4 3
1 3 3
edge from 1-->2edge from 2-->3edge from 1-->3

0 comments:

Post a Comment