FULL-WAVE RECTIFIER

__AIM__**:-**To find the Ripple factor and regulation of a Full-wave Rectifier with and without filter.

**:-**

__APPARATUS__Experimental Board

Transformer (6-0-6v).

P-n Diodes, (lN4007) ---2 No’s

Multimeters –2No’s

Filter Capacitor (100μF/25v) -

Connecting Wires

Load resistor, 1KΩ

**:-**

__THEORY__ The circuit of a center-tapped full wave rectifier uses two diodes D1&D2. During positive half cycle of secondary voltage (input voltage), the diode D1 is forward biased and D2is reverse biased.

The diode D1 conducts and current flows through load resistor R

_{L}. During negative half cycle, diodeD2 becomes forward biased and D1 reverse biased. Now, D2 conducts and current flows through the load resistor R

_{L}in the same direction. There is a continuous current flow through the load resistor R_{L}, during both the half cycles and will get unidirectional current as show in the model graph. The difference between full wave and half wave rectification is that a full wave rectifier allows unidirectional (one way) current to the load during the entire 360 degrees of the input signal and half-wave rectifier allows this only during one half cycle (180 degree).

__CIRCUIT DIAGRAM__**:-**

__PROCEDURE:__1. Connections are made as per the circuit diagram.

2. Connect the ac mains to the primary side of the transformer and the secondary side to the rectifier.

3. Measure the ac voltage at the input side of the rectifier.

4. Measure both ac and dc voltages at the output side the rectifier.

5. Find the theoretical value of the dc voltage by using the formula Vdc=2Vm/П

6. Connect the filter capacitor across the load resistor and measure the values of Vac and Vdc at the output.

7. The theoretical values of Ripple factors with and without capacitor are calculated.

8. From the values of Vac and Vdc practical values of Ripple factors are calculated. The practical values are compared with theoretical values.

__THEORITICAL CALCULATIONS:-__ Vrms = Vm/ √2

Vm =Vrms√2

Vdc=2Vm/П

(

**i)Without filter**: Ripple factor, r = √ ( Vrms/ Vdc )

^{2 }-1 = 0.482**(ii)With filter**:

**Ripple factor, r = 1/ (4√3 f C R**

_{L}) where f =50Hz

C =100µF

**R**

_{L}=1KΩ

__PRACTICAL CALCULATIONS__**:**

**Without filter**:-

Vac=

Vdc=

Ripple factor, r=Vac/Vdc

**With filters**:-

Vac=

Vdc=

Ripple factor=Vac/Vdc

**Without Filter:**

USING DMM | V_{ac}(v) | V_{dc}(v) | r= V/_{ac} V_{dc} |

| | |

**With Filter**

USING DMM | V_{ac}(v) | V_{dc}(v) | r= V/_{ac} V_{dc} |

| | |

**Without Filter**

Vrms = Vm/ √2 , Vdc=2Vm/П , Vac=√( Vrms

^{2}- Vdc^{2})

USING CRO | V_{m}(v) | V_{ac}(v) | V_{dc}(v) | r= V/_{ac} V_{dc} |

| | | |

**With Filter**

USINGCRO | V_{1}(V) | V_{2}(V) | V_{dc}= (V_{1}+V_{2})/2 | V_{ac}=(V_{1- }V_{2})/2√3 | r= V/_{ac} V_{dc} |

| | | | |

__PRECAUTIONS:__1. The primary and secondary side of the transformer should be carefully identified

2. The polarities of all the diodes should be carefully identified.

**:-**

__RESULT__The ripple factor of the Full-wave rectifier (with filter and without filter) is calculated.

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